6 – forty nine Prediction Method in Lotto
I would like to share with you a lotto 6/forty nine prediction system, that can increase a little bit the likelihood to guess the profitable numbers on the next draw. It is dependent on the intervals of the numbers, e.g. the variety of draws concerning two appearances of the same variety.
Suppose the variety 1 appears after seven draws, we write seven as very first variety of the sequence, then same variety 1 will come after 8 draws, we write 8 and so forth.
By this way we can construct the sequence of intervals for the variety 1, it looks something like: seven, 8, thirty, three, 10, seven, five, two …
The purpose is to get hold of a mathematical equation, so we can construct the intervals curve, making use of a sequence of numbers, that we currently know.
For example, making use of the sequence 1, two, three, four, five ….
I expended a lot of time, analysing the databases of the most 6/forty nine lotteries, hunting for suitable equation, to reproduce all intervals curves for the forty nine numbers.
Beneath is the equation:
Y = a + a3*sin(a4 + c1*cos(b1*X+e1) + d1*sin(b2*X+e2) + c2*cos(b3*X+e3) + d2*sin(b4*X+e4)+c3*cos(b5*X+e5) + d3*sin(b6*X+e6)+c4*cos(b7*X+e7) + d4*sin(b8*X+e8)+c5*cos(b9*X+e9) + d5*sin(b10*X+e10)+c6*cos(b11*X)+e11 + d6*sin(b12*X+e12)+c7*cos(b13*X+e13) + d7*sin(b14*X+e14))+a5*cos(a6 + c9*cos(b17*X+e17) + d9*sin(b18*X+e18) + c10*cos(b19*X+e19) + d10*sin(b20*X+e20)+c11*cos(b21*X+e21) + d11*sin(b22*X+e22)+c12*cos(b23*X+e23) + d12*sin(b24*X+e24)+c13*cos(b25*X+e25) + d13*sin(b26*X+e26)+c14*cos(b27*X+e27) + d14*sin(b28*X+e28))
The parametters values are the next:
c2 a hundred and sixty.540667471316
c5 -sixty nine.904752286696
c6 -eighty five.770268955927
d6 -sixty one.5407710429053
d9 -fifty eight.8664769640924
e13 a hundred and forty four.393758949961
e18 -sixty nine.3990298810884
e22 -seventy one.1614672890905
e28 -sixty seven.941409230581
e9 twenty five.157528943044
If we give a values for X as 1, two, three, four, five, 6, seven, 8, nine … the Y consequence will be a curve, really near to the intervals curve:
Coefficient of Various Dedication (R^two) = .9874443055
Due to the fact we know the intervals curve of the variety till its previous visual appeal, the purpose of the next stage will be to try to forecast the next point of the intervals curve,
making use of the curve we currently developed with the higher than equation.
Let us see for example, we know the previous 10 points of intervals curve of the variety 1:
it will looks something like 1, four, twelve, 31, 1, 1, two, 1, two, 10
Perfectly, now, lets construct our curve making use of the higher than equation, offering a values for X = 1, two, three, four, five, ……… 100 000 (exemplary)
Immediately after finding this work accomplished, lets compare the 10 points of the intervals curve with each and every set of 10 points of our curve, consider the Correlation operate for each and every two when compared sets, and discover the set of 10 points, that very best matches the 10 points of the intervals curve.
The 11th point of our curve will match the next point of intervals curve in three – seven % of all scenarios. This is surely a little bit superior than random guessing, but even now not sufficient to split the enormous residence edge of the lottery.
Have exciting and good luck!